FY_BCA_C_SLIP 20_2

Slip no : 20_2 multiplication of elememts of mxn matrix using dynamic memory allocation*/

#include<stdio.h> #include<stdlib.h>

int main()

{

int **ptr1, **ptr2, **ptr3; int row1, col1, row2, col2; int i, j, k;

printf("\nEnter number of rows for first matrix : "); scanf("%d", &row1);

printf("\nEnter number of columns for first matrix : "); scanf("%d", &col1);

printf("\nEnter number of rows for second matrix : "); scanf("%d", &row2);

printf("\nEnter number of columns for second matrix : "); scanf("%d", &col2);

if(col1 != row2)

{

printf("\nCannot multiply two matrices."); return(0);

}

ptr1 = (int **) malloc(sizeof(int *) * row1); ptr2 = (int **) malloc(sizeof(int *) * row2); ptr3 = (int **) malloc(sizeof(int *) * row1);

//allocatig memory for col of threematrices for(i=0; i<row1; i++)

ptr1[i] = (int *)malloc(sizeof(int) * col1);

for(i=0; i<row2; i++)

ptr2[i] = (int *)malloc(sizeof(int) * col2);

for(i=0; i<row1; i++)

ptr3[i] = (int *)malloc(sizeof(int) * col2);

// elements for first matrices

printf("\nEnter elements of first matrix :\n"); for(i=0; i< row1; i++)

{

for(j=0; j< col1; j++)

{

printf("\tA[%d][%d] = ",i, j); scanf("%d", &ptr1[i][j]);

}

}

//elements for second matrices

printf("\nEnter elements of second matrix :\n"); for(i=0; i< row2; i++)

{

for(j=0; j< col2; j++)

{

printf("\tB[%d][%d] = ",i, j); scanf("%d", &ptr2[i][j]);

}

}

// multiplication of two matrices/

for(i=0; i < row1; i++)

{

for(j=0; j < col1; j++)

{

ptr3[i][j] = 0; for(k=0; k<col2; k++)

ptr3[i][j] = ptr3[i][j] + ptr1[i][k] * ptr2[k][j];

}

}

// Printing the contents of third matrix./

printf("\n\nResultant matrix :"); for(i=0; i< row1; i++)

{

printf("\n\t\t\t"); for(j=0; j < col2; j++) printf("%4d", ptr3[i][j]);

}

return(0);

}